SATHEE: Electrostatics Question 581

Electrostatics Question 581

Question: A $10 μ F$ capacitor and a $20 μ F$ capacitor are connected in series across a $200 V$ supply line. The charged capacitors are then disconnected from the line and reconnected with their positive plates together and negative plates together and no external voltage is applied. What is the potential difference across each capacitor [MP PET 1997]

Options:

A) $\frac{400}{9} V$

B) $\frac{800}{9} V$

C) $400 V$

D) $200 V$

Show Answer

Answer:

Correct Answer: B

Solution:

Initially potential difference a cross each capacitor

$V_{1} = \frac{20}{(10 + 20)} \times 200 = \frac{400}{3} V$

and $V_{2} = \frac{10}{(10 + 20)} \times 200 = \frac{200}{3} V$

Finally common potential $V = \frac{C_{1} V_{1} + C_{2} V_{2}}{C_{1} + C_{2}}$

$V = \frac{10 \times \frac{400}{3} + 20 \times \frac{200}{3}}{(10 + 20)} = \frac{800}{9} V$

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Electrostatics Question 581

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