Electrostatics Question 580

Question: A capacitor of capacitance 5μF is connected . The internal resistance of the cell is0.5Ω . The amount of charge on the capacitor plate is [MP PET 1997]

Options:

A) 0μC

B) 5μC

C) 10μC

D) 25μC

Show Answer

Answer:

Correct Answer: C

Solution:

In steady state condition. No current flows through line (1).

Hence total current i=2.5(1+1+0.5)=1A

Potential difference a cross line (2) = potential difference a cross capacitor =1×2=2Volt

So, charge on capacitor = 5x 2 = 10 mC



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