Electrostatics Question 580
Question: A capacitor of capacitance $ 5\mu F $ is connected . The internal resistance of the cell is$ 0.5\Omega $ . The amount of charge on the capacitor plate is [MP PET 1997]
Options:
A) $ 0\mu C $
B) $ 5\mu C $
C) $ 10\mu C $
D) $ 25\mu C $
Show Answer
Answer:
Correct Answer: C
Solution:
In steady state condition. No current flows through line (1).
Hence total current $ i=\frac{2.5}{(1+1+0.5)}=1A $
Potential difference a cross line (2) = potential difference a cross capacitor $ =1\times 2=2Volt $
So, charge on capacitor = 5x 2 = 10 mC
