Electrostatics Question 580

Question: A capacitor of capacitance $ 5\mu F $ is connected . The internal resistance of the cell is$ 0.5\Omega $ . The amount of charge on the capacitor plate is [MP PET 1997]

Options:

A) $ 0\mu C $

B) $ 5\mu C $

C) $ 10\mu C $

D) $ 25\mu C $

Show Answer

Answer:

Correct Answer: C

Solution:

In steady state condition. No current flows through line (1).

Hence total current $ i=\frac{2.5}{(1+1+0.5)}=1A $

Potential difference a cross line (2) = potential difference a cross capacitor $ =1\times 2=2Volt $

So, charge on capacitor = 5x 2 = 10 mC



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