Electrostatics Question 576

Question: 100 capacitors each having a capacity of 10μF are connected in parallel and are charged by a potential difference of 100kV . The energy stored in the capacitors and the cost of charging them, if electrical energy costs 108 paise per kWh , will be [MP PET 1996; DPMT 2001]

Options:

A) 107 joule and 300 paise

B) 5×106joule and300 paise

C) 5×106joule and150 paise

D) 107joule and 150 paise

Show Answer

Answer:

Correct Answer: C

Solution:

Energy stored in the capacitor =12CV2×100

=12×10×106×(100×103)2×100=5×106J

Electric energy costs =108Paise per kWH

=108Paise3.6×106J \Total cost of charging =5×106×1083.6×106=150Paise



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