Electrostatics Question 569

Question: Two identical parallel plate capacitors are connected in series to a battery of 100V . A dielectric slab of dielectric constant 4.0 is inserted between the plates of second capacitor. The potential difference across the capacitors will now be respectively [MP PMT 1992]

Options:

A) 50 V, 50 V

B) 80 V, 20 V

C) 20 V, 80 V

D) 75 V, 25 V

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Answer:

Correct Answer: B

Solution:

Ceq=C×4C(C+4C)=4C5

Q=Ceq.V=4C5×100=80C

Hence V1=QC1=80CC1=80V and V2=80C4C=20V



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