SATHEE: Electrostatics Question 567

Electrostatics Question 567

Question: . A capacitor $4 μ F$ charged to 50 $V$ is connected to another capacitor of $2 μ F$ charged to 100 $V$ with plates of like charges connected together. The total energy before and after connection in multiples of $(10^{- 2} J)$ is [MP PMT 1992]

Options:

A) 1.5 and 1.33

B) 1.33 and 1.5

C) 3.0 and 2.67

D) 2.67 and 3.0

Show Answer

Answer:

Correct Answer: A

Solution:

The total energy before connection

$= \frac{1}{2} \times 4 \times 10^{- 6} \times {(50)}^{2} + \frac{1}{2} \times 2 \times 10^{- 6} \times {(100)}^{2}$

$= 1.5 \times 10^{- 2} J$

When connected in parallel $4 \times 50 + 2 \times 100 = 6 \times V$

therefore $V = \frac{200}{3}$ Total energy after connection

$= \frac{1}{2} \times 6 \times 10^{- 6} \times {(\frac{200}{3})}^{2} = 1.33 \times 10^{- 2} J$

Electrostatics Question 567

Question: . A capacitor $4 μ F$ charged to 50 $V$ is connected to another capacitor of $2 μ F$ charged to 100 $V$ with plates of like charges connected together. The total energy before and after connection in multiples of $(10^{- 2} J)$ is [MP PMT 1992]

Options:

Answer:

Solution:

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Electrostatics Question 567

Question: . A capacitor 4μF charged to 50 V is connected to another capacitor of 2μF charged to 100 V with plates of like charges connected together. The total energy before and after connection in multiples of (10−2J) is [MP PMT 1992]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: . A capacitor $4 μ F$ charged to 50 $V$ is connected to another capacitor of $2 μ F$ charged to 100 $V$ with plates of like charges connected together. The total energy before and after connection in multiples of $(10^{- 2} J)$ is [MP PMT 1992]