Electrostatics Question 563

Question: $ 0.2F $ capacitor is charged to $ 600V $ by a battery. On removing the battery, it is connected with another parallel plate condenser of 1F. The potential decreases to [MNR 1978; MP PET 2002]

Options:

A) $ 100\ volts $

B) $ 120\ volts $

C) $ 300\ volts $

D) $ 600\ volts $

Show Answer

Answer:

Correct Answer: A

Solution:

By using charge conservation $ 0.2\times 600=(0.2+1)V $ therefore $ V=\frac{0.2\times 600}{1.2}=100V $



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