Electrostatics Question 563

Question: 0.2F capacitor is charged to 600V by a battery. On removing the battery, it is connected with another parallel plate condenser of 1F. The potential decreases to [MNR 1978; MP PET 2002]

Options:

A) 100 volts

B) 120 volts

C) 300 volts

D) 600 volts

Show Answer

Answer:

Correct Answer: A

Solution:

By using charge conservation 0.2×600=(0.2+1)V therefore V=0.2×6001.2=100V



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