SATHEE: Electrostatics Question 562

Electrostatics Question 562

Question: A condenser having a capacity of 6mF is charged to 100 V and is then joined to an uncharged condenser of $14 μ F$ and then removed. The ratio of the charges on 6mF and 14mF and the potential of 6mF will be [MP PMT 1991]

Options:

A) $\frac{6}{14}$ and $50 v o l t$

B) $\frac{14}{6}$ and $30 v o l t$

C) $\frac{6}{14}$ and $30 v o l t$

D) $\frac{14}{6}$ and 0 $v o l t$

Show Answer

Answer:

Correct Answer: C

Solution:

Let $q_{1}, q_{2}$ be the charges on two condensers

$V = \frac{q_{1}}{6} = \frac{q_{2}}{14}$

therefore $\frac{q_{1}}{q_{2}} = \frac{6}{14} = \frac{3}{7}$

Also $q_{1} + q_{2} = 600$

therefore $q_{1} + \frac{14}{6} q_{1} = 600$

therefore $q_{1} = \frac{600}{20} \times 6$ $V = \frac{q_{1}}{6} = \frac{600}{20} = 30 v o l t$

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Electrostatics Question 562

Question: A condenser having a capacity of 6mF is charged to 100 V and is then joined to an uncharged condenser of 14μF and then removed. The ratio of the charges on 6mF and 14mF and the potential of 6mF will be [MP PMT 1991]

Options:

Answer:

Solution:

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Question: A condenser having a capacity of 6mF is charged to 100 V and is then joined to an uncharged condenser of $14 μ F$ and then removed. The ratio of the charges on 6mF and 14mF and the potential of 6mF will be [MP PMT 1991]