SATHEE: Electrostatics Question 544

Electrostatics Question 544

Question: A capacitor of capacity $C_{1}$ is charged to the potential of $V_{o}$ . On disconnecting with the battery, it is connected with a capacitor of capacity $C_{2}$ as . The ratio of energies before and after the connection of switch $S$ will be

Options:

A) $(C_{1} + C_{2}) / C_{1}$

B) $C_{1} / (C_{1} + C_{2})$

C) $C_{1} C_{2}$

D) $C_{1} / C_{2}$

Show Answer

Answer:

Correct Answer: A

Solution:

Energy (U) $= \frac{q^{2}}{2 C}$ .

q remains same so $U \propto \frac{1}{C}$

therefore $\frac{U_{B e f o r e}}{U_{A f t e r}} =$

$\frac{C_{1} + C_{2}}{C_{1}}$

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Electrostatics Question 544

Question: A capacitor of capacity C1 is charged to the potential of Vo . On disconnecting with the battery, it is connected with a capacitor of capacity C2 as . The ratio of energies before and after the connection of switch S will be

Options:

Answer:

Solution:

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Question: A capacitor of capacity $C_{1}$ is charged to the potential of $V_{o}$ . On disconnecting with the battery, it is connected with a capacitor of capacity $C_{2}$ as . The ratio of energies before and after the connection of switch $S$ will be