Electrostatics Question 538

Question: Two capacitances of capacity $ C _{1} $ and $ C _{2} $ are connected in series and potential difference $ V $ is applied across it. Then the potential difference across $ C _{1} $ will be [MP PMT 1985]

Options:

A) $ V\frac{C _{2}}{C _{1}} $

B) $ V\frac{C _{1}+C _{2}}{C _{1}} $

C) $ V\frac{C _{2}}{C _{1}+C _{2}} $

D) $ V\frac{C _{1}}{C _{1}+C _{2}} $

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Answer:

Correct Answer: C

Solution:

Charge flowing $ =\frac{C _{1}C _{2}}{C _{1}+C _{2}}V $ . So potential difference across $ C _{1}=\frac{C _{1}C _{2}V}{C _{1}+C _{2}}\times \frac{1}{C _{1}} $

$ =\frac{C _{2}V}{C _{1}+C _{2}} $



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