SATHEE: Electrostatics Question 538

Electrostatics Question 538

Question: Two capacitances of capacity $C_{1}$ and $C_{2}$ are connected in series and potential difference $V$ is applied across it. Then the potential difference across $C_{1}$ will be [MP PMT 1985]

Options:

A) $V \frac{C_{2}}{C_{1}}$

B) $V \frac{C_{1} + C_{2}}{C_{1}}$

C) $V \frac{C_{2}}{C_{1} + C_{2}}$

D) $V \frac{C_{1}}{C_{1} + C_{2}}$

Show Answer

Answer:

Correct Answer: C

Solution:

Charge flowing $= \frac{C_{1} C_{2}}{C_{1} + C_{2}} V$ . So potential difference across $C_{1} = \frac{C_{1} C_{2} V}{C_{1} + C_{2}} \times \frac{1}{C_{1}}$

$= \frac{C_{2} V}{C_{1} + C_{2}}$

Electrostatics Question 538

Question: Two capacitances of capacity $C_{1}$ and $C_{2}$ are connected in series and potential difference $V$ is applied across it. Then the potential difference across $C_{1}$ will be [MP PMT 1985]

Options:

Answer:

Solution:

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Syllabus

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Electrostatics Question 538

Question: Two capacitances of capacity C1 and C2 are connected in series and potential difference V is applied across it. Then the potential difference across C1 will be [MP PMT 1985]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Two capacitances of capacity $C_{1}$ and $C_{2}$ are connected in series and potential difference $V$ is applied across it. Then the potential difference across $C_{1}$ will be [MP PMT 1985]