Electrostatics Question 528

Question: $ n $ identical condensers are joined in parallel and are charged to potential$ V $ . Now they are separated and joined in series. Then the total energy and potential difference of the combination will be [MP PET 1993]

Options:

A) Energy and potential difference remain same

B) Energy remains same and potential difference is $ nV $

C) Energy increases $ n $ times and potential difference is $ nV $

D) Energy increases $ n $ times and potential difference remains same

Show Answer

Answer:

Correct Answer: B

Solution:

According to energy conservation, energy remains the same therefore $ U _{parallel}=U _{series} $

therefore $ \frac{1}{2}(nC)V^{2}=\frac{1}{2}( \frac{C}{n} )V{{’}^{2}} $

therefore V’ = nV ($ V’ $ = potential difference across series combination)



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