Electrostatics Question 522

Question: Two identical capacitors are joined in parallel, charged to a potential V and then separated and then connected in series i.e. the positive plate of one is connected to negative of the other [NCERT 1972, 73, 82; KCET 1993]

Options:

A) The charges on the free plates connected together are destroyed

B) The charges on the free plates are enhanced

C) The energy stored in the system increases

D) The potential difference in the free plates becomes 2V

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Answer:

Correct Answer: D

Solution:

Q1=CV and Q2=CV

Applying charge conservation CV1+CV2=Q1+Q2

CV1+CV2=2CV

therefore V1+V2=2V



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