Electrostatics Question 50

Question: Two metallic charged spheres whose radii are 20$ cm $ and 10$ cm $ respectively, have each 150$ micro-coulomb $ positive charge. The common potential after they are connected by a conducting wire is [MP PMT 1991]

Options:

A) $ 9\times 10^{6}\ volts $

B) $ 4.5\times 10^{6}\ volts $

C) $ 1.8\times 10^{7}\ volts $

D) $ 13.5\times 10^{6}\ volts $

Show Answer

Answer:

Correct Answer: A

Solution:

Common potential $ V=\frac{\text{Total charge }}{\text{Total capacitance}} $

$ V=\frac{150\times {{10}^{-6}}\times 2}{4\pi {\varepsilon _{0}}(10\times {{10}^{-2}}+20\times {{10}^{-2}})}=9\times 10^{6}V $



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