SATHEE: Electrostatics Question 492

Electrostatics Question 492

Question: Point charge $q_{1} = 2 μ C$ and $q_{2} = - 1 μ C$ are kept at points $x = 0$ and $x = 6$ respectively. Electrical potential will be zero at points [MP PMT 2004]

Options:

A) $x = 2$ and $x = 9$

B) $x = 1$ and $x = 5$

C) $x = 4$ and $x = 12$

D) $x = - 2$ and $x = 2$

Show Answer

Answer:

Correct Answer: C

Solution:

Potential will be zero at two points At internal point (M) : $\frac{1}{4 π ε_{0}} \times [\frac{2 \times 10^{- 6}}{(6 - l)} + \frac{(- 1 \times 10^{- 6})}{l}] = 0$

therefore l = 2 So distance of M from origin; x = 6 ? 2 = 4 At exterior point (N) : $\frac{1}{4 π ε_{0}} \times [\frac{2 \times 10^{- 6}}{(6 - l^{'})} + \frac{(- 1 \times 10^{- 6})}{l^{^{'}}}] = 0$

therefore $l^{'} = 6$ So distance of N from origin, x = 6 + 6 = 12

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Electrostatics Question 492

Question: Point charge q1=2μC and q2=−1μC are kept at points x=0 and x=6 respectively. Electrical potential will be zero at points [MP PMT 2004]

Options:

Answer:

Solution:

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Question: Point charge $q_{1} = 2 μ C$ and $q_{2} = - 1 μ C$ are kept at points $x = 0$ and $x = 6$ respectively. Electrical potential will be zero at points [MP PMT 2004]