Electrostatics Question 488

Question: The potential at a distance R/2 from the centre of a conducting sphere of radius R will be [RPMT 2003]

Options:

A) 0

B) $ \frac{Q}{8\pi {\varepsilon _{0}}R} $

C) $ \frac{Q}{4\pi {\varepsilon _{0}}R} $

D) $ \frac{Q}{2\pi {\varepsilon _{0}}R} $

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Answer:

Correct Answer: C

Solution:

Potential inside the conducting sphere is same as that of surface i.e. $ \frac{Q}{4\pi {\varepsilon _{0}}R} $



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