Electrostatics Question 486

Question: A charge produces an electric field of 1 N/C at a point distant 0.1 m from it. The magnitude of charge is [RPET 2002]

Options:

A) $ 1.11\times {{10}^{-12}}C $

B) $ 9.11\times {{10}^{-12}}C $

C) $ 7.11\times {{10}^{-6}}C $

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

$ E=9\times 10^{9}\frac{Q}{r^{2}} $

therefore $ Q=\frac{E\times r^{2}}{9\times 10^{9}}=\frac{1\times {{(0.1)}^{2}}}{9\times 10^{9}}=1.11\times {{10}^{-12}}C $



NCERT Chapter Video Solution

Dual Pane