Electrostatics Question 470

Question: A charge of 10 e.s.u. is placed at a distance of 2 cm from a charge of 40 e.s.u. and 4 cm from another charge of 20 e.s.u. The potential energy of the charge 10 e.s.u. is (in ergs) [CPMT 1976; MP PET 1989]

Options:

A) 87.5

B) 112.5

C) 150

D) 250

Show Answer

Answer:

Correct Answer: D

Solution:

Energy $ =\frac{10\times 40}{2}+\frac{10\times 20}{4}=250erg $



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