Electrostatics Question 437

Question: Two small spherical balls each carrying a charge $ Q=10\mu C $ (10 micro-coulomb) are suspended by two insulating threads of equal lengths 1m each, from a point fixed in the ceiling. It is found that in equilibrium threads are separated by an angle $ 60^{o} $ between them. What is the tension in the threads (Given: $ \frac{1}{(4\pi {\varepsilon _{0}})}=9\times 10^{9}Nm/C^{2} $ ) [MP PET 2001; Pb PET 2003]

Options:

A) 18 N

B) 1.8 N

C) 0.18 N

D) None of the above

Show Answer

Answer:

Correct Answer: B

Solution:

In equilibrium $ F _{e}=Tsin30^{o} $ , r = 1m therefore $ 9\times 10^{9}.\frac{Q^{2}}{r^{2}} $ =$ T\times \frac{1}{2} $

therefore $ 9\times 10^{9}.\frac{{{(10\times {{10}^{-6}})}^{2}}}{1^{2}}=T\times \frac{1}{2} $

$ \Rightarrow $ T = 1.8 N



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