Electrostatics Question 426

Question: The dimension of (1/2) ε0E2(ε0 : permittivity of free space; E : electric field) is [IIT-JEE (Screening) 2000; KCET 2000]

Options:

A) MLT1

B) ML2T2

C) ML1T2

D) ML2T1

Show Answer

Answer:

Correct Answer: C

Solution:

Energy density =EnergyVolume so it’s dimensions are ML2T2L3=[ML1T2]



NCERT Chapter Video Solution

Dual Pane