Electrostatics Question 42

Question: N identical spherical drops charged to the same potential V are combined to form a big drop. The potential of the new drop will be [MP PMT 1990, 2001; KCET 2000; Kerala PET 2002]

Options:

A) V

B) V/N

C) V×N

D) V×N2/3

Show Answer

Answer:

Correct Answer: D

Solution:

If the drops are conducting, then 43πR3=N(43πr3)

therefore R=N1/3r .

Final charge Q = Nq So final potential V=QR

=NqN1/3r=V×N2/3



NCERT Chapter Video Solution

Dual Pane