Electrostatics Question 405

Question: The electric field due to a charge at a distance of 3 m from it is 500 N/coulomb. The magnitude of the charge is [14πε0=9×109Nm2coulomb2] [MP PMT 2000]

Options:

A) 2.5 micro-coulomb

B) 2.0 micro-coulomb

C) 1.0 micro-coulomb

D) 0.5 micro-coulomb

Show Answer

Answer:

Correct Answer: D

Solution:

E=9×109×Qr2500=9×109×Q(3)2

therefore Q = 0.5 mC



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