Electrostatics Question 401

Question: An electron enters between two horizontal plates separated by 2mm and having a potential difference of 1000V. The force on electron is [JIPMER 1999]

Options:

A) $ 8\times {{10}^{-12}} $ N

B) $ 8\times {{10}^{-14}} $ N

C) $ 8\times 10^{9} $ N

D) $ 8\times 10^{14} $ N

Show Answer

Answer:

Correct Answer: B

Solution:

Force on electron F = QE $ =Q( \frac{V}{d} ) $

therefore $ F=(1.6\times {{10}^{-19}})( \frac{1000}{2\times {{10}^{-3}}} )=8\times {{10}^{-14}}N $



NCERT Chapter Video Solution

Dual Pane