Electrostatics Question 401

Question: An electron enters between two horizontal plates separated by 2mm and having a potential difference of 1000V. The force on electron is [JIPMER 1999]

Options:

A) 8×1012 N

B) 8×1014 N

C) 8×109 N

D) 8×1014 N

Show Answer

Answer:

Correct Answer: B

Solution:

Force on electron F = QE =Q(Vd)

therefore F=(1.6×1019)(10002×103)=8×1014N



NCERT Chapter Video Solution

Dual Pane