Electrostatics Question 399

Question: A proton is accelerated through 50,000 V. Its energy will increase by [JIPMER 1999]

Options:

A) 5000 eV

B) 8×1015 J

C) 5000 J

D) 50,000 J

Show Answer

Answer:

Correct Answer: B

Solution:

Kinetic energy K=Q.VK=(+e)(50000V)

=50000eV=50000×1.6×1019J=8×1015J



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