Electrostatics Question 396

Question: What is the potential energy of the equal positive point charges of $ 1\mu C $ each held 1 m apart in air [AMU 1999]

Options:

A) $ 9\times {{10}^{-3}}J $

B) $ 9\times {{10}^{-3}}eV $

C) $ 2eV/m $

D) Zero

Show Answer

Answer:

Correct Answer: A

Solution:

By using $ U=9\times 10^{9}\frac{Q _{1}Q _{2}}{r} $

therefore $ U=9\times 10^{9}\times \frac{{{10}^{-6}}\times {{10}^{-6}}}{1}=9\times {{10}^{-3}}J $



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