Electrostatics Question 390

Question: A sphere of radius 1cm has potential of 8000V , then energy density near its surface will be [RPET 1999]

Options:

A) 64×105J/m3

B) 8×103J/m3

C) 32J/m3

D) 2.83J/m3

Show Answer

Answer:

Correct Answer: D

Solution:

Energy density ue=12ε0E2=12×8.86×10−12×(Vr)2

=2.83J/m3

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