SATHEE: Electrostatics Question 383

Electrostatics Question 383

Question: Two spheres of radius $a$ and $b$ respectively are charged and joined by a wire. The ratio of electric field of the spheres is [CPMT 1999; JIPMER 2000; RPET 2000]

Options:

A) $a / b$

B) $b / a$

C) $a^{2} / b^{2}$

D) $b^{2} / a$

Show Answer

Answer:

Correct Answer: B

Solution:

Joined by a wire means they are at the same potential.

For same potential $\frac{k Q_{1}}{a_{1}} = \frac{k Q_{2}}{a_{2}}$

therefore $\frac{Q_{1}}{Q_{2}} = \frac{a}{b}$

Further, the electric field at the surface of the sphere having radius R and charge Q is
$\frac{E_{1}}{E_{2}} = \frac{k Q_{1} / a^{2}}{k Q_{2} / b_{2}} = \frac{Q_{1}}{Q_{2}} \times \frac{b^{2}}{a^{2}} = \frac{b}{a}$

Electrostatics Question 383

Question: Two spheres of radius $a$ and $b$ respectively are charged and joined by a wire. The ratio of electric field of the spheres is [CPMT 1999; JIPMER 2000; RPET 2000]

Options:

Answer:

Solution:

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Electrostatics Question 383

Question: Two spheres of radius a and b respectively are charged and joined by a wire. The ratio of electric field of the spheres is [CPMT 1999; JIPMER 2000; RPET 2000]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Two spheres of radius $a$ and $b$ respectively are charged and joined by a wire. The ratio of electric field of the spheres is [CPMT 1999; JIPMER 2000; RPET 2000]