SATHEE: Electrostatics Question 382

Electrostatics Question 382

Question: Two metal pieces having a potential difference of $800 V$ are $0.02 m$ apart horizontally. A particle of mass $1.96 \times 10^{- 15} k g$ is suspended in equilibrium between the plates. If $e$ is the elementary charge, then charge on the particle is [MP PET 1999]

Options:

A) $e$

B) $3 e$

C) $6 e$

D) $8 e$

Show Answer

Answer:

Correct Answer: B

Solution:

For equilibrium mg = qE $1.96 \times 10^{- 15} \times 9.8 = q \times (\frac{800}{0.02})$

therefore $q = \frac{1.96 \times 10^{- 15} \times 9.8 \times 0.02}{800}$

therefore $n \times 1.6 \times 10^{- 19} = \frac{1.96 \times 10^{- 15} \times 9.8 \times 0.02}{800}$

therefore n = 3.

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Electrostatics Question 382

Question: Two metal pieces having a potential difference of 800V are 0.02m apart horizontally. A particle of mass 1.96×10−15kg is suspended in equilibrium between the plates. If e is the elementary charge, then charge on the particle is [MP PET 1999]

Options:

Answer:

Solution:

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Question: Two metal pieces having a potential difference of $800 V$ are $0.02 m$ apart horizontally. A particle of mass $1.96 \times 10^{- 15} k g$ is suspended in equilibrium between the plates. If $e$ is the elementary charge, then charge on the particle is [MP PET 1999]