Electrostatics Question 381

Question: The electric potential V is given as a function of distance x (metre) by V=(5x2+10x−9)volt . Value of electric field at x=1 is [MP PET 1999]

Options:

A) 20V/m

B) 6V/m

C) 11V/m

D) −23V/m

Show Answer

Answer:

Correct Answer: A

Solution:

E=−dVdx=−ddx(5x2+10x−9)=−10x−10

at x=1

=−10×1−10=−20V/m

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