Electrostatics Question 379
Question: An alpha particle is accelerated through a potential difference of $ 10^{6}volt $ . Its kinetic energy will be [MP PMT/PET 1998]
Options:
A) $ 1MeV $
B) $ 2MeV $
C) $ 4MeV $
D) $ 8MeV $
Show Answer
Answer:
Correct Answer: B
Solution:
$ K=qV=2e\times 10^{6}J=\frac{2e\times 10^{6}}{e}eV=2MeV $
