SATHEE: Electrostatics Question 371

Electrostatics Question 371

Question: Four identical charges $+ 50 μ C$ each are placed, one at each corner of a square of side $2 m$ . How much external energy is required to bring another charge of $+ 50 μ C$ from infinity to the centre of the square $(Given \frac{1}{4 π ε_{0}} = 9 \times 10^{9} \frac{N m^{2}}{C^{2}})$

Options:

A) $64 J$

B) $41 J$

C) $16 J$

D) $10 J$

Show Answer

Answer:

Correct Answer: A

Solution:

Potential at the centre of square $V = 4 \times (\frac{9 \times 10^{9} \times 50 \times 10^{- 6}}{2 / \sqrt{2}}) = 90 \sqrt{2} \times 10^{4} V$

Work done in bringing a charge (q = 50 mC) from ¥ to centre (O) of the square is

$W = q (V_{0} - V_{\infty}) = q V_{0}$

therefore $W = 50 \times 10^{- 6} \times 90 \sqrt{2} \times 10^{4} = 64 J$

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Electrostatics Question 371

Question: Four identical charges +50μC each are placed, one at each corner of a square of side 2m . How much external energy is required to bring another charge of +50μC from infinity to the centre of the square (Given14πε0=9×109Nm2C2)

Options:

Answer:

Solution:

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Question: Four identical charges $+ 50 μ C$ each are placed, one at each corner of a square of side $2 m$ . How much external energy is required to bring another charge of $+ 50 μ C$ from infinity to the centre of the square $(Given \frac{1}{4 π ε_{0}} = 9 \times 10^{9} \frac{N m^{2}}{C^{2}})$