SATHEE: Electrostatics Question 366

Electrostatics Question 366

Question: What is the magnitude of a point charge due to which the electric field $30 c m$ away has the magnitude $2 n e w t o n / c o u l o m b$

$[1 / 4 π ε_{0} = 9 \times 10^{9} N m^{2} / C^{2}]$ [MP PMT 1996]

Options:

A) $2 \times 10^{- 11} c o u l o m b$

B) $3 \times 10^{- 11} c o u l o m b$

C) $5 \times 10^{- 11} c o u l o m b$

D) $9 \times 10^{- 11} c o u l o m b$

Show Answer

Answer:

Correct Answer: A

Solution:

Electric field due to a point charge $E = \frac{q}{4 π ε_{0} r^{2}}$ $q = E \times 4 π ε_{0} r^{2} = 2 \times \frac{1}{9 \times 10^{9}} \times {(\frac{30}{100})}^{2}$ = 2 x $10^{- 11}$ C

Electrostatics Question 366

Question: What is the magnitude of a point charge due to which the electric field $30 c m$ away has the magnitude $2 n e w t o n / c o u l o m b$

Options:

Answer:

Solution:

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Electrostatics Question 366

Question: What is the magnitude of a point charge due to which the electric field 30cm away has the magnitude 2newton/coulomb

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: What is the magnitude of a point charge due to which the electric field $30 c m$ away has the magnitude $2 n e w t o n / c o u l o m b$