Electrostatics Question 365

Question: The distance between a proton and electron both having a charge 1.6×1019coulomb , of a hydrogen atom is 1010metre . The value of intensity of electric field produced on electron due to proton will be [MP PET 1996]

Options:

A) 2.304×1010N/C

B) 14.4V/m

C) 16V/m

D) 1.44×1011N/C

Show Answer

Answer:

Correct Answer: D

Solution:

E=q4πε0r2

=9×109×1.6×1019(1010)2=1.44×1011N/C



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