Electrostatics Question 360

Question: Deutron and $ \alpha - $ particle are put $ 1{AA} $ apart in air. Magnitude of intensity of electric field due to deutron at $ \alpha - $ particle is [MP PET 1995]

Options:

A) Zero

B) $ 2.88\times 10^{11}newton/coulomb $

C) $ 1.44\times 10^{11}newton/coulomb $

D) $ 5.76\times 10^{11}newton/coulomb $

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Answer:

Correct Answer: C

Solution:

Due to deutron, intensity of electric field at 1 Å distance,

$ E=\frac{1}{4\pi {\varepsilon _{0}}}.\frac{e}{r^{2}} $

$ =\frac{9\times 10^{9}\times 1.6\times {{10}^{-19}}}{{{10}^{-20}}}=1.44\times 10^{11}N/C. $



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