Electrostatics Question 360
Question: Deutron and $ \alpha - $ particle are put $ 1{AA} $ apart in air. Magnitude of intensity of electric field due to deutron at $ \alpha - $ particle is [MP PET 1995]
Options:
A) Zero
B) $ 2.88\times 10^{11}newton/coulomb $
C) $ 1.44\times 10^{11}newton/coulomb $
D) $ 5.76\times 10^{11}newton/coulomb $
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Answer:
Correct Answer: C
Solution:
Due to deutron, intensity of electric field at 1 Å distance,
$ E=\frac{1}{4\pi {\varepsilon _{0}}}.\frac{e}{r^{2}} $
$ =\frac{9\times 10^{9}\times 1.6\times {{10}^{-19}}}{{{10}^{-20}}}=1.44\times 10^{11}N/C. $