Electrostatics Question 359

Question: A particle A has charge +q and a particle B has charge +4q with each of them having the same mass m . When allowed to fall from rest through the same electric potential difference, the ratio of their speed vAvB will become [BHU 1995; MNR 1991; UPSEAT 2000; Pb PET 2004]

Options:

A) 2:1

B) 1:2

C) 1:4

D) 4:1

Show Answer

Answer:

Correct Answer: B

Solution:

Using v=2QVm

therefore vQ

therefore vAvB=QAQB=q4q=12



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