SATHEE: Electrostatics Question 355

Electrostatics Question 355

Question: Three particles, each having a charge of $10 μ C$ are placed at the corners of an equilateral triangle of side $10 c m$ . The electrostatic potential energy of the system is (Given $\frac{1}{4 π ε_{0}} = 9 \times 10^{9} N - m^{2} / C^{2}$ ) [MP PMT 1994]

Options:

A) Zero

B) Infinite

C) $27 J$

D) $100 J$

Show Answer

Answer:

Correct Answer: C

Solution:

For pair of charge $U = \frac{1}{4 π ε_{0}} . \frac{q_{1} q_{2}}{r}$

$U_{S y s t e m} = \frac{1}{4 π ε_{0}} [\frac{10 \times 10^{- 6} \times 10 \times 10^{- 6}}{10 / 100} .$

$. + \frac{10 \times 10^{- 6} \times 10 \times 10^{- 6}}{10 / 100} + \frac{10 \times 10^{- 6} \times 10 \times 10^{- 6}}{10 / 100}]$

$= 3 \times 9 \times 10^{9} \times \frac{100 \times 10^{- 12} \times 100}{10} = 27 J$

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Electrostatics Question 355

Question: Three particles, each having a charge of 10μC are placed at the corners of an equilateral triangle of side 10cm . The electrostatic potential energy of the system is (Given 14πε0=9×109N−m2/C2 ) [MP PMT 1994]

Options:

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Question: Three particles, each having a charge of $10 μ C$ are placed at the corners of an equilateral triangle of side $10 c m$ . The electrostatic potential energy of the system is (Given $\frac{1}{4 π ε_{0}} = 9 \times 10^{9} N - m^{2} / C^{2}$ ) [MP PMT 1994]