SATHEE: Electrostatics Question 340

Electrostatics Question 340

Question: . The insulation property of air breaks down at $E = 3 \times 10^{6}$ volt/metre. The maximum charge that can be given to a sphere of diameter $5 m$ is approximately (in coulombs) [MP PMT 1990]

Options:

A) $2 \times 10^{- 2}$

B) $2 \times 10^{- 3}$

C) $2 \times 10^{- 4}$

D) $2 \times 10^{- 5}$

Show Answer

Answer:

Correct Answer: B

Solution:

$E = \frac{1}{4 π ε_{0}} \times \frac{q}{r^{2}} = 9 \times 10^{9} \times \frac{q}{r^{2}}$ $q = \frac{E \times r^{2}}{9 \times 10^{9}} = \frac{3 \times 10^{6} \times {(2.5)}^{2}}{9 \times 10^{9}} = 2.0833 \times 10^{- 3}$ q should be less than 2.0833 $10^{- 3}$ .

In the given set of options 2 $10^{- 3}$ is the maximum charge which is smaller than 2.0833 $10^{- 3}$ .

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Electrostatics Question 340

Question: . The insulation property of air breaks down at E=3×106 volt/metre. The maximum charge that can be given to a sphere of diameter 5m is approximately (in coulombs) [MP PMT 1990]

Options:

Answer:

Solution:

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Question: . The insulation property of air breaks down at $E = 3 \times 10^{6}$ volt/metre. The maximum charge that can be given to a sphere of diameter $5 m$ is approximately (in coulombs) [MP PMT 1990]