SATHEE: Electrostatics Question 327

Electrostatics Question 327

Question: The electric potential $V$ at any point O (x, y, z all in metres) in space is given by $V = 4 x^{2} v o l t$ . The electric field at the point $(1 m, 0, 2 m)$ in $v o l t / m e t r e$ is [IIT 1992; RPET 1999; MP PMT 2001]

Options:

A) 8 along negative $X -$ axis

B) 8 along positive $X -$ axis

C) 16 along negative $X -$ axis

D) 16 along positive $Z -$ axis

Show Answer

Answer:

Correct Answer: A

Solution:

The electric potential $V (x, y, z) = 4 x^{2} v o l t$

Now $\vec{E} = - (\hat{i} \frac{\partial V}{\partial x} + \hat{j} \frac{\partial V}{\partial y} + \hat{k} \frac{\partial V}{\partial z})$ Now $\frac{\partial V}{\partial x} = 8 x, \frac{\partial V}{\partial y} = 0$

and $\frac{\partial V}{\partial z} = 0$

Hence $\vec{E} = - 8 x \hat{i}$

, so at point (1m, 0, 2m) $\vec{E} = - 8 \hat{i} v o l t / m e t r e$ or 8 along negative X-axis.

Electrostatics Question 327

Question: The electric potential $V$ at any point O (x, y, z all in metres) in space is given by $V = 4 x^{2} v o l t$ . The electric field at the point $(1 m, 0, 2 m)$ in $v o l t / m e t r e$ is [IIT 1992; RPET 1999; MP PMT 2001]

Options:

Answer:

Solution:

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Electrostatics Question 327

Question: The electric potential V at any point O (x, y, z all in metres) in space is given by V=4x2volt . The electric field at the point (1m,0,2m) in volt/metre is [IIT 1992; RPET 1999; MP PMT 2001]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: The electric potential $V$ at any point O (x, y, z all in metres) in space is given by $V = 4 x^{2} v o l t$ . The electric field at the point $(1 m, 0, 2 m)$ in $v o l t / m e t r e$ is [IIT 1992; RPET 1999; MP PMT 2001]