SATHEE: Electrostatics Question 32

Electrostatics Question 32

Question: Between the plates of a parallel plate condenser, a plate of thickness $t_{1}$ and dielectric constant $k_{1}$ is placed. In the rest of the space, there is another plate of thickness $t_{2}$ and dielectric constant $k_{2}$ . The potential difference across the condenser will be [MP PET 1993]

Options:

A) $\frac{Q}{A ε_{0}} (\frac{t_{1}}{k_{1}} + \frac{t_{2}}{k_{2}})$

B) $\frac{ε_{0} Q}{A} (\frac{t_{1}}{k_{1}} + \frac{t_{2}}{k_{2}})$

C) $\frac{Q}{A ε_{0}} (\frac{k_{1}}{t_{1}} + \frac{k_{2}}{t_{2}})$

D) $\frac{ε_{0} Q}{A} (k_{1} t_{1} + k_{2} t_{2})$

Show Answer

Answer:

Correct Answer: A

Solution:

Potential difference across the condenser

$V = V_{1} + V_{2} = E_{1} t_{1} + E_{2} t_{2} = \frac{σ}{K_{1} ε_{0}} t_{1} + \frac{σ}{K_{2} ε_{0}} t_{2}$

therefore $V = \frac{σ}{ε_{0}} (\frac{t_{1}}{K_{1}} + \frac{t_{2}}{K_{2}}) = \frac{Q}{A ε_{0}} (\frac{t_{1}}{K_{1}} + \frac{t_{2}}{K_{2}})$

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Electrostatics Question 32

Question: Between the plates of a parallel plate condenser, a plate of thickness t1 and dielectric constant k1 is placed. In the rest of the space, there is another plate of thickness t2 and dielectric constant k2 . The potential difference across the condenser will be [MP PET 1993]

Options:

Answer:

Solution:

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