Electrostatics Question 317

Question: Two electric dipoles of moment P and 64 P are placed in opposite direction on a line at a distance of 25 cm. The electric field will be zero at point between the dipoles whose distance from the dipole of moment P is [MP PET 2003]

Options:

A) 5 cm

B) $ \frac{25}{9} $ cm

C) 10 cm

D) $ \frac{4}{13} $ cm

Show Answer

Answer:

Correct Answer: A

Solution:

Suppose neutral point N lies at a distance x from dipole of moment p or at a distance x2 from dipole of 64 p. At N |E. F. due to dipole |= |E. F. due to dipole ‚| therefore $ \frac{1}{4\pi {\varepsilon _{0}}}.\frac{2p}{x^{3}}=\frac{1}{4\pi {\varepsilon _{0}}}.\frac{2(64p)}{{{(25-x)}^{3}}} $

therefore $ \frac{1}{x^{3}}=\frac{64}{{{(25-x)}^{3}}} $

therefore x = 5 cm.



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