SATHEE: Electrostatics Question 313

Electrostatics Question 313

Question: For a dipole $q = 2 \times 10^{- 6} C$ and $d = 0.01 m$ . Calculate the maximum torque for this dipole if $E = 5 \times 10^{5} N / C$ [RPMT 2003]

Options:

A) $1 \times 10^{- 3} N m^{- 1}$

B) $10 \times 10^{- 3} N m^{- 1}$

C) $10 \times 10^{- 3} N m$

D) $1 \times 10^{2} N m^{2}$

Show Answer

Answer:

Correct Answer: C

Solution:

$τ_{max} = p E = q (2 l) E$

$= 2 \times 10^{- 6} \times 0.01 \times 5 \times 10^{5}$

$= 10 \times 10^{- 3} N - m$

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Electrostatics Question 313

Question: For a dipole q=2×10−6C and d=0.01m . Calculate the maximum torque for this dipole if E=5×105N/C [RPMT 2003]

Options:

Answer:

Solution:

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Question: For a dipole $q = 2 \times 10^{- 6} C$ and $d = 0.01 m$ . Calculate the maximum torque for this dipole if $E = 5 \times 10^{5} N / C$ [RPMT 2003]