Electrostatics Question 313
Question: For a dipole $ q=2\times {{10}^{-6}}C $ and $ d=0.01m $ . Calculate the maximum torque for this dipole if $ E=5\times 10^{5}N/C $ [RPMT 2003]
Options:
A) $ 1\times {{10}^{-3}}N{{m}^{-1}} $
B) $ 10\times {{10}^{-3}}N{{m}^{-1}} $
C) $ 10\times {{10}^{-3}}Nm $
D) $ 1\times 10^{2}Nm^{2} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ {\tau _{\max }}=pE=q(2l)E $
$ =2\times {{10}^{-6}}\times 0.01\times 5\times 10^{5} $
$ =10\times {{10}^{-3}}N\text{-}m $
