Electrostatics Question 313

Question: For a dipole $ q=2\times {{10}^{-6}}C $ and $ d=0.01m $ . Calculate the maximum torque for this dipole if $ E=5\times 10^{5}N/C $ [RPMT 2003]

Options:

A) $ 1\times {{10}^{-3}}N{{m}^{-1}} $

B) $ 10\times {{10}^{-3}}N{{m}^{-1}} $

C) $ 10\times {{10}^{-3}}Nm $

D) $ 1\times 10^{2}Nm^{2} $

Show Answer

Answer:

Correct Answer: C

Solution:

$ {\tau _{\max }}=pE=q(2l)E $

$ =2\times {{10}^{-6}}\times 0.01\times 5\times 10^{5} $

$ =10\times {{10}^{-3}}N\text{-}m $



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