Electrostatics Question 307

Question: The electric intensity due to a dipole of length 10 cm and having a charge of 500μC , at a point on the axis at a distance 20 cm from one of the charges in air, is [CBSE PMT 2001]

Options:

A) 6.25×107 N/C

B) 9.28×107 N/C

C) 13.1×1111 N/C

D) 20.5×107 N/C

Show Answer

Answer:

Correct Answer: A

Solution:

By using E=9×109.2pr(r2l2)2;

where p=(500×106)×(10×102)=5×105 ,

r = 25 cm = 0.25 m, l = 5 cm = 0.05 m E=9×109×2×5×105×0.25(0.25)2(0.05)22

=6.25×107N/C



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