Electrostatics Question 301

Question: Two opposite and equal charges $ 4\times {{10}^{-8}}coulomb $ when placed $ 2\times {{10}^{-2}}cm $ away, form a dipole. If this dipole is placed in an external electric field $ 4\times 10^{8}newton/coulomb $ , the value of maximum torque and the work done in rotating it through $ 180{}^\circ $ will be [MP PET 1996]

Options:

A) $ 64\times {{10}^{-4}}Nm $ and $ 64\times {{10}^{-4}}J $

B) $ 32\times {{10}^{-4}} $ Nm and $ 32\times {{10}^{-4}}J $

C) $ 64\times {{10}^{-4}}Nm $ and $ 32\times {{10}^{-4}}J $

D) $ 32\times {{10}^{-4}}Nm $ and $ 64\times {{10}^{-4}}J $

Show Answer

Answer:

Correct Answer: D

Solution:

Dipole moment $ p=\text{4}\times \text{1}{{0}^{\text{8}}}~\times \text{2}\times \text{1}{{0}^{\text{4}}}=\text{ 8}\times \text{1}{{0}^{\text{12}}}m $

Maximum torque $ =pE=\text{8}\times \text{1}{{0}^{\text{12}}}\times \text{4}\times \text{1}{{0}^{\text{8}}} $

$ =\text{ 32}\times \text{1}{{0}^{\text{4}}}Nm $

Work done in rotating through $ \text{18}{{0}^{\text{o}}}=\text{ 2}pE $

$ =\text{ 2}\times \text{32}\times \text{1}{{0}^{\text{4}}}=\text{ 64}\times \text{1}{{0}^{\text{4}}}J $



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