SATHEE: Electrostatics Question 286

Electrostatics Question 286

Question: A 4 mF capacitor, a resistance of 2.5 MW is in series with 12 V battery. Find the time after which the potential difference across the capacitor is 3 times the potential difference across the resistor. [Given ln(2)= 0.693] [IIT-JEE (Screening) 2005]

Options:

A) 200 and 180 V

B) 180 and 135 V

C) 160 and 80 V

D) 140 and 20 V

Show Answer

Answer:

Correct Answer: B

Solution:

$V = V_{0} (e^{- λ t})$

After 1 seconds $V_{1} = 320 (e^{- λ}) \Rightarrow 240 = 320 (e^{- λ}) \Rightarrow e^{- λ} = \frac{3}{4}$

After 2 seconds $V_{2} = 320 {(e^{- λ})}^{2} = 320 \times {(\frac{3}{4})}^{2} = 180 v o l t$

After 3 seconds $V_{3} = 320 {(e^{- λ})}^{3} = 320 \times {(\frac{3}{4})}^{3} = 135 v o l t$

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Electrostatics Question 286

Question: A 4 mF capacitor, a resistance of 2.5 MW is in series with 12 V battery. Find the time after which the potential difference across the capacitor is 3 times the potential difference across the resistor. [Given ln(2)= 0.693] [IIT-JEE (Screening) 2005]

Options:

Answer:

Solution:

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