Electrostatics Question 286

Question: A 4 mF capacitor, a resistance of 2.5 MW is in series with 12 V battery. Find the time after which the potential difference across the capacitor is 3 times the potential difference across the resistor. [Given ln(2)= 0.693] [IIT-JEE (Screening) 2005]

Options:

A) 200 and 180 V

B) 180 and 135 V

C) 160 and 80 V

D) 140 and 20 V

Show Answer

Answer:

Correct Answer: B

Solution:

$ V=V _{0}({{e}^{-\lambda t}}) $

After 1 seconds $ V _{1}=320({{e}^{-\lambda }})\Rightarrow 240=320({{e}^{-\lambda }})\Rightarrow {{e}^{-\lambda }}=\frac{3}{4} $

After 2 seconds $ V _{2}=320{{({{e}^{-\lambda }})}^{2}}=320\times {{( \frac{3}{4} )}^{2}}=180volt $

After 3 seconds $ V _{3}=320{{({{e}^{-\lambda }})}^{3}}=320\times {{( \frac{3}{4} )}^{3}}=135volt $



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