Electrostatics Question 274

Question: Four metallic plates each with a surface area of one side A are placed at a distance d from each other. The plates are connected as shown in the circuit diagram. Then the capacitance of the system between a and b is

Options:

A) VAB=VBC=100V

B) VAB=75V, VBC=25 V

C) VAB=25V, VBC=75 V

D) VAB=VBC=50 V

Show Answer

Answer:

Correct Answer: C

Solution:

Ceq=(3+3)×(1+1)(3+3)+(1+1)+1=(6×26+2)+1

=52μF Q=C×V=52×100=250μC

Charge in 6μF branch =VC=(6×26+2)100

=150μC

VAB=1506=25V and VBC=100VAB=75V



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