Electrostatics Question 273

Question: Condenser $ A $ has a capacity of $ 15\mu F $ when it is filled with a medium of dielectric constant 15. Another condenser $ B $ has a capacity of $ 1\mu F $ with air between the plates. Both are charged separately by a battery of$ 100\ V $ . After charging, both are connected in parallel without the battery and the dielectric medium being removed. The common potential now is [MNR 1994]

Options:

A) $ \frac{3V}{K+2} $

B) $ \frac{3V}{K} $

C) $ \frac{V}{K+2} $

D) $ \frac{V}{K} $

Show Answer

Answer:

Correct Answer: A

Solution:

$ q _{1}=2CV, $

$ q _{2}=CV $

Now condenser of capacity C is filled with dielectric K, therefore C2 = KC As charge is conserved $ q _{1}+q _{2}=(C _{2}^{’}+2C)V’ $

therefore $ V’=\frac{3CV}{(K+2)C}=\frac{3V}{K+2} $



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