Electrostatics Question 261

Question: A charged particle q is shot towards another charged particle Q which is fixed, with a speed ν . It approaches Q upto a closest distance r and then returns. If q were given a speed 2ν , the closest distances of approach would be [AIEEE 2004]

Options:

A) 250J

B) 750J

C) 1225J

D) 1475J

Show Answer

Answer:

Correct Answer: D

Solution:

Energy =12ε0E2×(A×d)

=12ε0(V2d2)Ad

=12×8.85×1012×(105)2×25×1060.75×103=1475J



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