SATHEE: Electrostatics Question 257

Electrostatics Question 257

Question: A point charge of 40 stat coulomb is placed 2 cm in front of an earthed metallic plane plate of large size. Then the force of attraction on the point charge is

Options:

A) $\frac{q_{2}}{b^{2}} - \frac{q_{3}}{a^{2}} \sin θ$

B) $\frac{q_{2}}{b^{2}} - \frac{q_{3}}{a^{2}} \cos θ$

C) $\frac{q_{2}}{b^{2}} + \frac{q_{3}}{a^{2}} \sin θ$

D) $\frac{q_{2}}{b^{2}} + \frac{q_{3}}{a^{2}} \cos θ$

Show Answer

Answer:

Correct Answer: C

Solution:

$F_{2}$ = Force applied by $q_{2}$ on $- q_{1}$

$F_{3}$ = Force applied by $(- q_{3})$ on $q_{1}$ x-component of Net force on $- q_{1}$ is $F_{x} = F_{2} + F_{3} sin θ$

$= k \frac{q_{1} q_{2}}{b^{2}} + k . \frac{q_{1} q_{3}}{a^{2}} \sin θ$

therefore $F_{x} = k [\frac{q_{1} q_{2}}{b^{2}} + \frac{q_{1} q_{3}}{a^{2}} \sin θ]$

therefore $F_{x} = k \cdot q_{1} [\frac{q_{2}}{b^{2}} + \frac{q_{3}}{a^{2}} \sin θ]$

therefore $F_{x} \propto (\frac{q_{2}}{b^{2}} + \frac{q_{3}}{a^{2}} \sin θ)$

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Electrostatics Question 257

Question: A point charge of 40 stat coulomb is placed 2 cm in front of an earthed metallic plane plate of large size. Then the force of attraction on the point charge is

Options:

Answer:

Solution:

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