SATHEE: Electrostatics Question 249

Electrostatics Question 249

Question: Two equal point charges are fixed at $x = - a$ and $x = + a$ on the x-axis. Another point charge Q is placed at the origin. The Change in the electrical potential energy of Q, when it is displaced by a small distance $x$ along the x-axis, is approximately proportional to [IIT-JEE (Screening) 2002]

Options:

A) 10

B) $5 \sqrt{2}$

C) $10 \sqrt{2}$

D) 20

Show Answer

Answer:

Correct Answer: C

Solution:

Body moves along the parabolic path.

For vertical motion : By using v = u + at therefore $v_{y} = 0 + \frac{Q E}{m} . t = \frac{10^{- 6} \times 10^{3}}{10^{- 3}} \times 10 = 10 m / sec$

For horizontal motion -It’s horizontal velocity remains the same i.e. after 10 sec, horizontal velocity of body vx = 10 m/sec. Velocity after 10 sec $v = \sqrt{v_{x}^{2} + v_{y}^{2}}$

$= 10 \sqrt{2} m / s e c$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Electrostatics Question 249

Question: Two equal point charges are fixed at x=−a and x=+a on the x-axis. Another point charge Q is placed at the origin. The Change in the electrical potential energy of Q, when it is displaced by a small distance x along the x-axis, is approximately proportional to [IIT-JEE (Screening) 2002]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu