Electrostatics Question 242

Question: Charge $ q $ is uniformly distributed over a thin half ring of radius $ R $ . The electric field at the centre of the ring is [Roorkee 1999]

Options:

A) $ 6.0\times 10^{27}C $

B) $ 2.67\times 10^{7}C $

C) $ 6\times 10^{23}C $

D) $ 1.67\times 10^{23}C $

Show Answer

Answer:

Correct Answer: B

Solution:

$ Q=ne $ ;

where n = number of moles $ ~\times \text{6}.0\text{2}\times \text{1}{{0}^{\text{23}}}\times \text{1}0 $

therefore $ Q=\frac{500}{18}\times 6.02\times 10^{23}\times 10\times 1.6\times {{10}^{-19}}=2.67\times 10^{7}C $



NCERT Chapter Video Solution

Dual Pane