SATHEE: Electrostatics Question 240

Electrostatics Question 240

Question: Electric potential is given by $V = 6 x - 8 x y^{2} - 8 y + 6 y z - 4 z^{2}$ Then electric force acting on $2 C$ point charge placed on origin will be [RPET 1999]

Options:

A) + 2

B) ? 1

C) ? 2

D) Zero

Show Answer

Answer:

Correct Answer: A

Solution:

$\int_{- \infty}^{0} - \vec{E} \cdot \vec{d l}$ = potential at centre of non-conducting ring $= \frac{1}{4 π ε_{0}} \times \frac{q}{r} = \frac{9 \times 10^{9} \times 1.11 \times 10^{- 10}}{0.5} = 2 v o l t$

Electrostatics Question 240

Question: Electric potential is given by $V = 6 x - 8 x y^{2} - 8 y + 6 y z - 4 z^{2}$ Then electric force acting on $2 C$ point charge placed on origin will be [RPET 1999]

Options:

Answer:

Solution:

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Electrostatics Question 240

Question: Electric potential is given by V=6x−8xy2−8y+6yz−4z2 Then electric force acting on 2C point charge placed on origin will be [RPET 1999]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Electric potential is given by $V = 6 x - 8 x y^{2} - 8 y + 6 y z - 4 z^{2}$ Then electric force acting on $2 C$ point charge placed on origin will be [RPET 1999]