Electrostatics Question 236
Question: A charge
Options:
A) Electric field near
B) Charge density at
C) Potential at
D) Total electric field flux through the surface of the cavity is
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Answer:
Correct Answer: C , D
Solution:
Under electrostatic condition, all points lying on the conductor are in same potential. Therefore, potential at A = potential at B.
From Gauss’s theorem, total flux through the surface of the cavity will be
Not: q Instead of an elliptical cavity, if it would had been a spherical cavity then options (a) and (b) were also correct.
Under electrostatic condition, all points lying on the conductor are in same potential. Therefore, potential at A = potential at B.
From Gauss’s theorem, total flux through the surface of the cavity will be
